0=x^2+1.5x-5

Solution for 0=x^2+1.5x-5 equation:

0=x^2+1.5x-5

We move all terms to the left:

0-(x^2+1.5x-5)=0

We add all the numbers together, and all the variables

-(x^2+1.5x-5)=0

We get rid of parentheses

-x^2-1.5x+5=0

We add all the numbers together, and all the variables

-1x^2-1.5x+5=0

a = -1; b = -1.5; c = +5;
Δ = b2-4ac
Δ = -1.52-4·(-1)·5
Δ = 22.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{22.25}}{2*-1}=\frac{1.5-\sqrt{22.25}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{22.25}}{2*-1}=\frac{1.5+\sqrt{22.25}}{-2}
$